Just some initial thoughts as I think about this ....
Let's take the newer version of the KCA (forgive me if I'm not formulating it exactly right):
1. If the Universe began to exist, it had a cause.
2. The Universe began to exist.
C. Therefore, the Universe had a cause.
Let's not forget that a person who doesn't limit what possibly exists to material reality would not limit P1 to the physical universe and would conclude that if there are immaterial things which began to exist then these would need a cause too. I would say that this is why P1 of Kalam is not making a claim specifically about the universe ...
P1. If something begins to exist then it must have a cause of its existence.
This can be reworded to express a set relation. So, there is a set B and every member of B began to exist. P1 is saying that every member of B must also have a cause. P2 is saying that that the universe is a member of B. So ...
P1. If X is a member of B (the set things which begin to exist) then X has a cause.
P2. The universe is a member of B.
C. Therefore, the universe has a cause.
How do set relations of this type impact on these probabilities? It seems intuitive that it cannot be ignored because we're now dealing with states of affairs that are conditionally embedded.
1. If my neighbour's dog is in the park, it's wearing a dog-sweater.
2. My neighbour's dog is in the park.
C. Therefore, my neighbour's dog is wearing a dog-sweater.
Edit: My neighbours dog only wears a sweater if it's in the park (it's not really the same structure otherwise).
A nitpick here. If the dog only wears a sweater at the park then this actually needs to be expressed as ...
P1. If my neighbour's dog is wearing a sweater then it is in the park.
P2. My neighbour's dog is wearing a sweater.
C. Therefore, my neighbour's dog is in the park.
Which also gives us ...
P1. If my neighbour's dog is wearing a sweater then it is in the park.
P2. My neighbour's dog is not in the park.
C. Therefore, my neighbour's dog is not wearing a sweater.
The above doesn't mean that the dog must be wearing a sweater if it is in the park. That would be affirming the consequent. Again, we can think in terms of a set relation. A is the set of activities engaged in by your neighbours dog. P is a subset of A, and is the activity of being at the park. S is a subset of P and is the dog wearing a sweater.
So again, how would this type of embedded scenario affect overall probability, if at all?